How can I have a function wait until after a model update to run?

Comments

• Shmuel Kamensky

  October 27, 2016 edited November 2, 2017

  Thanks to Matt and Pat for your posts on this!
  
  https://community.skuid.com/skuid/top...
  
  
  The main line of code from the below sample that provides the solution is

  
  $.when(initialUpdateOrOtherDeferredFunction()).done([printSuccess,doStuffAfterUpdateAttempt]).fail([printFailure,doStuffAfterUpdateAttempt]);

  See below for the rest of the solution

  
  $ = skuid.$;
  try{
      
      //both done and fail function take a function or array of functions as parameters. I chose an array for both to print sucess state.
  //https://api.jquery.com/jQuery.when/
  //https://api.jquery.com/deferred.done/
  //https://api.jquery.com/deferred.fail/
  //"Since deferred.done() returns the deferred object, other methods of the deferred object can be chained to this one"
  //this is why .fail can be appended to .done
      $.when(initialUpdateOrOtherDeferredFunction()).done([printSuccess,doStuffAfterUpdateAttempt]).fail([printFailure,doStuffAfterUpdateAttempt]);
      
  }
  catch(e){
      
      console.log(e);
  }
  
  function initialUpdateOrOtherDeferredFunction(){
  var mod = skuid.model.getModel('modelName');
  //do pre-processing stuff to your model here
  //return the deferred promise
  return mod.updateData();
  
  }
  
  
  function printFailure(){
   
      console.log('Failure');
      
  }
  function printSuccess(){
   
      console.log('Success');
      
  }
  function doStuffAfterUpdateAttempt(){
  //do stuff
  //do stuff
  //repeat stuff https://www.youtube.com/watch?v=nt9c0UeYhFc
  }

  0